- #1
laurabon
- 16
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- Homework Statement
- Why the sets E1={z∈E:|f(z)|<M} and E2={z∈E:|f(z)|=M}} are both open?
- Relevant Equations
- E1={z∈E:|f(z)|<M}
E2={z∈E:|f(z)|=M}}
In the maximum modulus therem we have two sets $E1={z∈E:|f(z)|<M}E2={z∈E:|f(z)|=M}}$ I know that the set E1 is open because pre image of an open set. But should't be also E2 closed because pre image of only a point ?
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