- #1
aboredperson
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- Homework Statement
- Given three rigid 1.00-Liter containers at 25o C filled with 1.00 mole of helium gas, 2.00 moles of neon gas, and 3.00 moles of argon gas respectively. When all three gases are pumped into a fourth 1.00-Liter container, what is the volume occupied by the neon gas in the final mixture?
a) 1.00L b) 2.00L c) 3.00L d) 0.167L. E) 0.333L
- Relevant Equations
- PV=nRT
P=pressure(atm) V= volume (L) n= Moles R= 0.0821 T= Temperature(K)
PV=nRT
P*1L = 6 moles * 0.0821*298 (I added up all the moles and solved for pressure)
P =146.79 atm
146.79 atm * V = 2 moles Ar * 0.0821* 298 (I plugged in the moles for argon and solved for volume)
V= 0.333 L
Answer key says the answer is 1 Liter. Where did I go wrong?
P*1L = 6 moles * 0.0821*298 (I added up all the moles and solved for pressure)
P =146.79 atm
146.79 atm * V = 2 moles Ar * 0.0821* 298 (I plugged in the moles for argon and solved for volume)
V= 0.333 L
Answer key says the answer is 1 Liter. Where did I go wrong?