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elcotufa
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Homework Statement
Niobium Nb has the BCC crystal with a lattice parameter of a= .3294 nm
Find the planar concentrations of atoms per m^2 of the (100, (110) and (111) planes.
The 100 plane has 1 atom on the plane (1/4 times 4)
the 110 plane has 2 atoms on the plane and using pythagorean theorem the long side is a*sqrt(2)
http://www.gly.uga.edu/schroeder/geol6550/111.jpeg [Broken]
best pic I could find for the 111 plane
Now for the last plane (111) this is what I did
the area would be 1/2 base * height
the base is [tex]a*\sqrt2[/tex] and
pythagorean theorem to find the height is a^2 and half of the long side from plane (110) squared [tex]\sqrt{a^2+\frac{2a^2}4}=.4034nm[/tex]
[tex]
\frac12(.4034)10^{-9}(.3294)10^{-9}
[/tex]
Now how many atoms are on the plane? and are there mistakes in what I have done so far?
And how many atoms would that (111) plane have in a FCC model?
Answer would have number of atoms over area
Thanks for the help
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