- #1
tremain74
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- Homework Statement
- I have a problem that says a stone is dropped from a balloon that is ascending at a uniform rate of 10 m/s. If it takes the stone 10 s to reach the ground, how high was the balloon at the instant the stone was dropped? The answer is 485m.
- Relevant Equations
- I am using the projectile motion. ay = -9.8m/s^2 for negative gravity. Vy = -9.8 + V0sin0. V0 is initial velocity. Sin0 is sin of theta. y = -4.9 t^2 + v0*t* Sin0.
ay = -9.8. Vy = -9.8 + v0*Sin0. y = -4.9*t^2 + v0*t*Sin0. By using formula of y, my solution was -4.9(10s)^2 + (10m/s)(10s)Sin0. I assumed that y was equal to 0. Since -4.9 is m/s^2 the answer would be -490m + 100m*Sin0. Therefore I assumeed Sin0 = 490/100.