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How can space expand when space is not a physical thing? I’ve heard some say that is not expanding but rather it is getting less dense, which to me implies the same thing.
Didn't you ask this question before?PhanthomJay said:How can space expand when space is not a physical thing? I’ve heard some say that is not expanding but rather it is getting less dense, which to me implies the same thing.
I don’t remember asking it. But thanks for responsePeroK said:Didn't you ask this question before?
If space is expanding, then that's your evidence that it can expand, whether it's a physical thing or not.
What do you mean when you say it is not a physical thing? While it is true that what ”space” is is a rather arbitrary separation from spacetime. Cosmology generally uses a very particular coordinate system in which the universe is spatially homogeneous and isotropic. It is in those coordinates we talk about the expansion of space, which is nothing else than noting that the distance between so-called comoving objects (essentially objects at rest wrt the CMB or, equivalently, the cosmic frame) grow with time.PhanthomJay said:How can space expand when space is not a physical thing? I’ve heard some say that is not expanding but rather it is getting less dense, which to me implies the same thing.
No, it's an expansion of space over time - specifically that's how it's described in comoving coordinates.PhanthomJay said:And is time expanding also, being part of spacetime?
Locally (in a small enough spacetime region) it is possible to make a change of coordinates to the locally Minkowski coordinates. In those coordinates, comoving objects are indeed moving apart so it is a matter of coordinates. Hence, this is a matter of nomenclature and interpretation in a particular coordinate system.PhanthomJay said:Thanks, but why would it not be that the galaxies, not space, are moving apart as physical objects that are "spatially extended" (I borrowed that "term" from Einstein)?
Whether you like it or not is irrelevant. The only relevant thing is how accurately it describes the theory. As far as analogies go, it is a surprisingly appropriate one for the description using cosmological coordinates.PhanthomJay said:I don't particularly like the balloon analogy. And is time expanding also, being part of spacetime?
OK, now answer us this: where did you disappear to for 387 days? (from Jul 8 '22 till Jul 30 '23)PhanthomJay said:Once again, I want to thank you all for your time and responses.
I suppose this implies that an expanding flat space corresponds to a curved spacetime. That's right?PeroK said:More generally, the coordinate-free description is that spacetime is curved.
Hah, Dave , nice sense of humor! And good research! I've had some issues this past year, hope to be a regular again.DaveC426913 said:OK, now answer us this: where did you disappear to for 387 days? (from Jul 8 '22 till Jul 30 '23)
In general, yes. There are however some pathological counter examples. The best fit Lambda-CDM model of our universe not counting among those examples.Jaime Rudas said:I suppose this implies that an expanding flat space corresponds to a curved spacetime. That's right?
Here is the curvature of that spacetime, according to Wikipedia:Jaime Rudas said:I suppose this implies that an expanding flat space corresponds to a curved spacetime. That's right?
One clarification is probably appropriate here: what you quoted from Wikipedia only gives the Ricci tensor, which is only a piece of the Riemann tensor. But in this particular case, the other piece of the Riemann tensor, the Weyl tensor, is zero, so the Ricci tensor does capture all of the spacetime curvature. In general that will not be the case.Hill said:Here is the curvature of that spacetime
Thanks a lot. I wondered about the rest of Riemann tensor. Should've asked.PeterDonis said:One clarification is probably appropriate here: what you quoted from Wikipedia only gives the Ricci tensor, which is only a piece of the Riemann tensor. But in this particular case, the other piece of the Riemann tensor, the Weyl tensor, is zero, so the Ricci tensor does capture all of the spacetime curvature. In general that will not be the case.