Understanding Riemann Integrable Functions: Interpreting D&K Pages 427-428

I am not sure of the overall purpose of the concepts developed below regarding Riemann integrable functions with compact support ... nor am I sure of the details ... so I am sketching out the meaning as I understand it in 2 dimensions and depicting the relevant entities in diagrams ... I am hoping that someone can indicate that my interpretation of the ideas is correct and/or point out misinterpretations, shortcomings and errors ...

On D&K pages 427 and 428 we find the following text concerning Riemann integrable functions with compact support ... note that I am assuming the overall purpose of developing the notion of Riemann integrable functions with compact support is to create the linear space of Theorem 6.2.8 together with the other results of the theorem ...

To try to ensure that I understand the details I am translating the text into the two dimensional case and briefly explaining how I interpret the text ... I also attempt to depict the ideas in diagrams ...

As I said above ... I am hoping that someone can indicate that my interpretation of the ideas is correct and/or point out misinterpretations, shortcomings and errors ...Now ... we let \(\displaystyle f : \mathbb{R^2} \to \mathbb{R} \) be a function such that:

\(\displaystyle f \) is bounded on \(\displaystyle \mathbb{R^2} \) and zero outside a bounded subset \(\displaystyle A \subset \mathbb{R^2} \)

If \(\displaystyle f \) is Riemann integrable over \(\displaystyle B \) , the number \(\displaystyle \int_B f(x) dx \) is independent of the choice of B ... since it only depends on A ... and other rectangles such as B' containing A will give the same result ... that is \(\displaystyle \int_B f(x) dx \) = \(\displaystyle \int_{B'} f(x) dx \) ... since the only non-zero values of f are coming from the set A which is in all rectangles satisfying (6.7) ... ... ... Is that correct?

This situation is depicted in Figure 1 below ...Does Figure 1 correctly and validly depict the situation described in the scanned text above from D&K ...?
Now ... let B' be another rectangle satisfying (6.7) ... ... ... ... ... see Figure 2 below ...
In Figure 2 clearly \(\displaystyle B = (B \cap B' ) \cup ( B \text{ \ } B' ) \)

\(\displaystyle B \cap B' \) is a two dimensional rectangle

and

\(\displaystyle B \text{ \ } B' = B_1 \cup B_2 \)Consequently \(\displaystyle \{ B \cap B' \} \cup \{ B_i \ | \ i = 1,2 \} \) is a partition of B ... ...We have \(\displaystyle \int_{ B_i } f(x) dx \text{ for } i = 1, 2 \text{ because } f(x) =0 \text{ for } x = \text{ int}(B_i) \subset \mathbb{R^2} \text{ \ } B' \) ... ...But ... why isn't \(\displaystyle \int_{ B_i } f(x) dx \) zero for the boundary of the \(\displaystyle B_i \) as well ... ?

Is the above a correct interpretation of D&K's text as scanned above?Help will be appreciatedPeter

Hi Peter

Nice job once again looking to $\mathbb{R}^{2}$. Your pictures are also very well done and illustrate the concepts really well.

You asked a number of questions in this post and, as far as I can tell, your answers and intuition are correct. A few additional notes are:

1. "presumably \(\displaystyle f(x) =0 \) for those \(\displaystyle x \) that are inside \(\displaystyle B \) and outside \(\displaystyle A \) ... ... Is that correct?" Yes, this is correct because if $x\notin A$, then $f(x)=0.$
2. I have not read Duistermaat & Kolk so I don't know exactly how they plan to utilize bounded functions of compact support. However, the golden rule behind all calculus principles is to use what you know to approximate what you don't know. Bounded functions of compact support are well-behaved and will likely be used to approximate their more unruly counterparts in an attempt to rigorously define a Riemann integral for these more nuanced cases.
3. "But ... why isn't $\displaystyle\int_{B_{i}}f(x)dx$ zero for the boundary of the $B_{i}$ as well ... ?" It is zero. The boundary of the $B_{i}$ are 1-dimensional "hyperplanes" (though we commonly refer to 1-dimensional hyperplanes as "lines/line segments/intervals/etc") in $\mathbb{R}^{2}$, so they have measure/2-dimensional area = 0. See bottom of page 423 of Duistermaat & Kolk.

As I mentioned, everything in your post looks pretty good. I tried to point out the things that seemed to warrant an additional comment. If there's something you're still looking to dig deeper on, feel free to let me know.

Thanks GJA …

… working through your post now …

Looks really helpful …

Thanks again,

Peter