Determine Force for inclining platform

In summary, the conversation discusses the acceleration of a load and its dependence on cylinder geometry. It is also mentioned that the load is calculated at 12,000 kg and questions are raised about the safety of the support. The conversation ends with the thread being closed due to the discussion being deemed dangerous.
  • #1
jr5
3
0
TL;DR Summary
A hydraulic actuator force, F is 3000m from the right is lifting the platform upwards. The load 12000kg is UDL. How do I calculate for F?
inclined_beam.jpg
 
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  • #2
Is it accelerating the load? ##F## will also be a function of the cylinder geometry.
 
  • #3
No it's not accelerating the load. The cylinder geometry will be depending on the calculated force.
 
  • #4
Moment: 12,000 kg at 3.000 m = 36,000 kg⋅m .
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
 
  • #5
jr5 said:
The load 12000kg is UDL. How do I calculate for F?
The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?
 
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  • #6
berkeman said:
The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?
It's not for company, it's a mockup.
 
  • #7
jr5 said:
It's not for company, it's a mockup.
I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?
 
  • #8
berkeman said:
I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?
Jeopardy.
 
  • #9
DeBangis21 said:
Jeopardy.
You are not helping your case to keep this thread open; thread is now closed per the "no dangerous discussions" clause in the PF Rules (see INFO at the top of the page).
 

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